作业帮=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.
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![=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.](/uploads/image/z/11495430-54-0.jpg?t=%3D2%E2%88%AB%5Bu%26%23178%3B%2F%281%2Bu%29%5Ddu%3D2%E2%88%AB%5B%28u-1%29%2B1%2F%28u%2B1%29%5Ddu+%E8%BF%99%E4%B8%80%E6%AD%A5%E6%98%AF%E6%80%8E%E4%B9%88%E6%B1%82%E5%87%BA%E6%9D%A5%E7%9A%84.)
=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.
=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.
=2∫[u²/(1+u)]du=2∫[(u-1)+1/(u+1)]du 这一步是怎么求出来的.
u²/(1+u)=(u²-1+1)/(1+u)=u-1+1/(u+1)