作业帮化简函数解析式f(x)=2[sin(π/4+x)]^2-√3cos2x-1,x∈R
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/12 15:02:33
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化简函数解析式f(x)=2[sin(π/4+x)]^2-√3cos2x-1,x∈R
化简函数解析式f(x)=2[sin(π/4+x)]^2-√3cos2x-1,x∈R
化简函数解析式f(x)=2[sin(π/4+x)]^2-√3cos2x-1,x∈R
f(x)=2[sin(π/4+x)]^2-√3cos2x-1
=2[√2/2(sinx+cosx)]^2-√3cos2x-1
=1+sin2x-√3cos2x-1
=2(cos(-π/3)sin2x+sin(-π/3)cos2x)
=2sin(2x-π/3)
或者：
f(x)=sin2x-√3cos2x
=2[sin(π/6)sin2x-cos(π/6)cos2x]
=-2cos(2x+π/6)