(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒...(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒成立,

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(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒...(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒成立,

(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒...(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒成立,
(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒...
(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒成立,求a的取值范围

(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒...(1)一元二次不等式ax^2+bx+2>0的解集是(-1/2,-1/3),求a+b的值?(2)若x∈R,不等式ax^2+ax+1>0恒成立,
ax^2+bx+2>0的解集为-1/2

1,ax平方+bx+2=0的2个根为x1=-1/2,x2=1/3,
韦达定理:x1+x2=-b/a,x1*x2=2/a,
-1/2+1/3=-b/a,-1/2*1/3=2/a,解方程组得:a=-12,b=-2,a+b=-14;
2,
ax^2+ax+1=0无实数解,△=a平方-4*a*1<0,(a-2)平方<4,0

(1)ax^2+bx+2>0的解集是(-1/2,-1/3),知道-1/2和-1/3恰好是ax^2+bx+2=0的两个根,将x=-1/2和x=-1/3代入ax^2+bx+2=0,解得:a=12,b=10,所以a+b=22。
(2)a>0,且图形恒在X轴上方,a²-4a<0 即0<a <4

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We open room now! ( Changchun personalized hotel! each of which so much in love .)Is as ' color '!

Changchun , a simple type style hotel , Cost nearly billion yuan ,

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