已知sin2α=a,cos2α=b,求tan(α+π/4)的值.

已知sin2α=a,cos2α=b,求tan(α+π/4)的值.
已知sin2α=a,cos2α=b,求tan(α+π/4)的值.

已知sin2α=a,cos2α=b,求tan(α+π/4)的值.
tan(α+π/4)=(1+tanα)/(1-tanα)
=(sinα+cosα)/(cosα-sinα)
=(sinα+cosα)^2/(cosα^2-sinα^2)
=(1+sin2α)/cos2α
=(1+a)/b