作业帮设f(x)=ax²+bx+c f(x+1)+f(x-1) =2ax²+2bx+2a+2c
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设f(x)=ax²+bx+c f(x+1)+f(x-1) =2ax²+2bx+2a+2c
设f(x)=ax²+bx+c f(x+1)+f(x-1) =2ax²+2bx+2a+2c
设f(x)=ax²+bx+c f(x+1)+f(x-1) =2ax²+2bx+2a+2c
f(x)=ax²+bx+c
故：f(x+1)+f(x-1)
=a（x+1）²+b（x+1）+c +a（x-1）²+b（x-1）+c
=2ax²+2bx+2a+2c