A 1.778g sample of a component of the light petroleum distillate called naphtha is found to yield5.450g CO2(g) and 2.602g H2O(l) on complete combustion.Use the masses of carbon dioxide,CO2,and water,H2O,to determine the empirical formula of the alkan

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A 1.778g sample of a component of the light petroleum distillate called naphtha is found to yield5.450g CO2(g) and 2.602g H2O(l) on complete combustion.Use the masses of carbon dioxide,CO2,and water,H2O,to determine the empirical formula of the alkan

A 1.778g sample of a component of the light petroleum distillate called naphtha is found to yield5.450g CO2(g) and 2.602g H2O(l) on complete combustion.Use the masses of carbon dioxide,CO2,and water,H2O,to determine the empirical formula of the alkan
A 1.778g sample of a component of the light petroleum distillate called naphtha is found to yield5.450g CO2(g) and 2.602g H2O(l) on complete combustion.
Use the masses of carbon dioxide,CO2,and water,H2O,to determine the empirical formula of the alkane component.
Express your answer as a chemical formula.
写出化学式就好了 我算出来的CH比是3:

A 1.778g sample of a component of the light petroleum distillate called naphtha is found to yield5.450g CO2(g) and 2.602g H2O(l) on complete combustion.Use the masses of carbon dioxide,CO2,and water,H2O,to determine the empirical formula of the alkan
CH比3:7,应该是己烷,C6H14

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