matlab：1.x=1：pi/4:5 这里的“/”表示什么?数值呢?subplot(2,2,1) 括号里的2 2 1又分别表示什么?2.矩阵的reshape的意义在哪里?3.ctranspose的共轭转置是怎么计算的?为什么我的结果和转置一样?4.x=rand(1,8)

matlab的solve用法定义syms x y a1 a2equ1=1/120 - ((2*a2)/81 + (pi*a1)/12 + pi^2*(a2/405 + 1/12) + (pi^3*a1)/120)/pi^4equ2=-(a2/128 + (2*pi*a1)/81 + pi^2*(a2/960 + 2/81) + (pi^3*a1)/405 - pi^4/405)/pi^5输入solve('方程1', '方程2', 'a1', 'a1') 求大神解答一下我这MATLAB程序哪里有问题x=[0:0.01:1]b=[(2*pi)/45,pi/18,pi/12,pi/6,pi/3,pi/2,(2*pi)/3]a=1./(.4*tan(b./2))y=a.*x.^2plot(x,y) matlab提示Error:Incomplete or misformed expression or statement.x=0:2*pi:100;s=20*(4*x/pi-(1/(2*pi))*sin(8*pi*x/pi);plot(x,s);求指导. MATLAB计算无穷级数for X=2:1:20; for Y=2:1:5; syms n; f=400/pi.*sinh(n*pi*Y/20).*sin(n*pi*X/20)/n/sinh(n*pi/4)+200/pi.*sinh(n*pi*(5-Y)/20).*sin(n*pi*X/20)/n/sinh(n*pi/4); f1=symsum(f,n) end;end;计算结果应该是一 matlab 构造向量x=0:pi/10:2*pi ​ matlab 解隐函数方程,用matlab求x 怎么求不出来?已知方程（2*pi*0.00152)/0.00000063)*((1+*0.00152*(sin((2*pi*x)/0.00000063))^2)^(-2))*(sin(4*pi*x)/0.00000063)=y Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 其中0 MATLAB中,x=0:pi/100: matlab三维图程序：[X,Y]=meshgrid([200:2:300],[-pi/4:pi/100:pi/4]);M=-pi/4:pi/100:pi/4;f=sqrt(1-((1600+(X.*cos(M+pi/4)-0.707*X+40*sin(Y)).^2+(X.*sin(M+pi/4)-0.707*X-40*cos(Y)).^2-(0.707*X-40*sin(Y)).^2-(0.707*X+40*cos(Y)).^2)./(80*X)).^2);Z=(pi/ matlab 作图 x轴坐标显示的问题如题,我的程序是这样的N=10;x=linspace(-4*pi,4*pi,1000);y=abs((1./N).*(sin((x.*N)./2)./sin(x./2)).*exp(-i.*((N-1)./2).*x));plot(y)图像做出来以后是这样：怎么把x坐标轴变成是-4pi到4pi 怎么用matlab计算出pi/2=x+arccos(tan(pi/4-x/2)中未知数x的值 matlab中y=(0.5+3.*sin(x*pi/180)./(1+x^2)).*cos(x*pi/180);哪里错了? matlab里面求有约束条件的多元函数极值问题所求函数z=2*pi*x*y+4*pi*x^2约束条件pi*x^2*y=350x>=1能不能用fmincon这个函数来解决, matlab解一元三次方程写完代码运行出错,我写的代码如下：syms xL = 1:100;for i=1:length(L)x0 = solve('0.1125*tan(11*pi/36)*L(i)*x^3 - (tan(5*pi/36) + tan(pi/6))*(0.1125*tan(2*pi/9)*tan(11*pi/36)*L(i) + 1)*x^2 + (0.1125*tan(11*pi/36 matlab中画三维离散点,参数s是关于点的变量,想利用colorbar实现每个点的颜色对应a的值,即4维图x=[];y=[];z=[];s=[];for a1=2/3*pi:pi/20:17/12*pi;for a2=-7/6*pi:pi/20:-1/2*pi;for a3=-1/6*pi:pi/20:2/3*pi;b1=cos(a1)*cos(a2)*cos Matlab程序编写和出图u(x,t) = 10 + 5*cos(2*pi*t/T) + (1 + cos(2*pi*t/T))*x/5 + sum{n=1 to n=N} ( (10/pi*n [(T/2*pi) * sin(2*pi*t/T) - (25/(pi*n))^2 cos(2*pi*t/T)] * sin(pi*n*x/25) )I need it once with T=1 and once with T=365.Also for N you can matlab中is not a valid expression or equation.x=solve('2/3*14.3*pi*500^3*(sin(x*pi))^3/pi-(sin(pi*x)+sin((1.25-2*x)*pi))*450*x*14.3*pi*500^2*(1-sin(2*pi*x)/(2*pi*x))/(pi*(3x-1.25)）=402.86','x')Error using ==> solve' 2/3*14.3*pi*500^3*(sin(x*pi))^3 如何用matlab画x=2sint,y=cost,z=4t,t=-pi:pi图象