(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两种方式解答喔.

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(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两种方式解答喔.

(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两种方式解答喔.
(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...
(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两种方式解答喔.

(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两种方式解答喔.
是这样的形式吗?[x/(x+y)+2y/(x+y)]×[xy/(x+y)]÷(1/x+1/y)
一:原式=(x+2y)/(x+y) ×[xy/(x+2y)]÷[(x+y)/xy] =x²y²/(x+y)²
二:原式=xy/(x+y)÷(1/x+1/y)=x²y²/(x+y)²