设数列{an}的前n项和为Sn,若{an}和{根号sn+n}都是公差为d的等差数列,则a1=

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设数列{an}的前n项和为Sn,若{an}和{根号sn+n}都是公差为d的等差数列,则a1=

设数列{an}的前n项和为Sn,若{an}和{根号sn+n}都是公差为d的等差数列,则a1=
设数列{an}的前n项和为Sn,若{an}和{根号sn+n}都是公差为d的等差数列,则a1=

设数列{an}的前n项和为Sn,若{an}和{根号sn+n}都是公差为d的等差数列,则a1=
依题意得√(sn+n)=dn,sn=d^2*n^2-n
s(n-1)= d^2*(n-1)^2-(n-1)
an=sn-s(n-1)=2d^2*n-d*d-1
an=dn+c
2d*d=d
d=1/2
an=n/2-5/4
a1=-3/4

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