将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式

将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式 将sinx+siny+sinz-sin(x+y+z)化为积的形式 m=(sinx)/sin(y-z),n=(siny)/sin（z－x）,p=（sinz）/sin（x－y）,求mn+np+pm. 三角不等式证明证明sin(x+y)+sin(y+z)+sin(z+x)>sinx+siny+sinz+sin(x+y+z) 证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+y)/2) 已知x,y,z属于(0,派/2),sin^2x+sin^2y+sin^2z=1,求(sinx+siny+sinz)/(cosx+cosy+cosz)的最大值 1.已知8cos(2x+y)+5cosy=0,求tan(x+y)*tanx的值.2.已知关于x的方程x^2+px+q=0的两根是tanx,tany,求sin(x+y)/cos(x-y)的值.3.化简:sin(x-y)/(sinx*siny)+sin(y-z)/(siny*sinz)+sin(z-x)/(sinz*sinx). sinx+siny+sinz=0;cosx+cosy+cosz=0;求cos(x-y) 已知sinx+siny+sinz=0,cosx+cosy+cosz=0 则cos（x-y）=______ 要详解 sinx+siny+sinz=0,cosx+cosy+cosz=0,求cos（y-z）的值. 已知sinx+siny+sinz=cosx+cosy+cosz=0,求tan(x+y+z)+tanxtanytanz的值 证明sin(x+y)sin(x-y)=sinx-siny 一道关于三角函数的不等式证明题已知0≤x＜y＜z≤π求证：（siny-sinx）/(y-x)>(sinz-siny)/(z-y) |sinx-siny| 为什么sinx*cosy-cosx*siny=sin(x-y) 求函数z=sinx+siny+sin(x+y)(0 存在sin( x -y) = sinX-sinY吗 sinx siny-sin(x y)如何化简