[(x∨2+y∨2)-(x-y)∨2+2y(x-y)]÷4y+4,其中2x-y=18先化简,后求值

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[(x∨2+y∨2)-(x-y)∨2+2y(x-y)]÷4y+4,其中2x-y=18先化简,后求值

[(x∨2+y∨2)-(x-y)∨2+2y(x-y)]÷4y+4,其中2x-y=18先化简,后求值
[(x∨2+y∨2)-(x-y)∨2+2y(x-y)]÷4y+4,其中2x-y=18
先化简,后求值

[(x∨2+y∨2)-(x-y)∨2+2y(x-y)]÷4y+4,其中2x-y=18先化简,后求值
[(x∨2+y∨2)-(x-y)∨2+2y(x-y)]÷4y+4=[x^2 + y^2 - x^2 + 2xy - y^2 +2xy - 2y^2]÷4y+4
= (4xy-2y^2)/4y+4 = (2x - y)/2 +4
因为2x - y = 18
所以 原式 = 18/2 +4 = 9 +4 = 13

=(4xy-2y^2)/4y+4
=x-y/2+4
=9+4
=13