sqrt(1-sin(4x))求0到pi/2上定积分

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 05:40:12
sqrt(1-sin(4x))求0到pi/2上定积分

sqrt(1-sin(4x))求0到pi/2上定积分
sqrt(1-sin(4x))求0到pi/2上定积分

sqrt(1-sin(4x))求0到pi/2上定积分
这道题需要讨论范围,所以拆开最好……
积分符号内式子sqrt(1-sin(4x))的化sqrt(sin2x-cos2x)^2,由于根号下的正负不同,所以化成从0到π/8的cos2x-sin2x的定积分加上π/8到π/2的sin2x-cos2x的定积分,这样就好求啦,最后结果为根号2
这道题重要的是根据定义域分成两部分,

sqrt(1-sin(4x))求0到pi/2上定积分 已知cos(x)=sqrt(10)/10,x属于(0,pi/2),求sin(pi/4+2x)的值 matlab菜鸟,y=sqrt(1+(0.5*sin(power(3.14*x),2)));错在哪里?想求根号(1+(0.15sin(pi*x))^2从0到2的积分) matlab rotate程序求大神修改t=0:pi/1000:3.5*pi;k=fix(2*t/pi)+1;x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k.*cos(t);y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k.*sin(t);h=plot(x,y,'r');m=pi:pi/20:4.5*pi;n=fix(2*m/pi)-1;x0=2*cos(1.25*pi);y0=2*sin(1.25*pi);x2= ∫sqrt(4-4*sin^2(x)) dx 范围[2pi/3,0] 求(Sin^3x-Sin^5x)^1/2(根号)在0到PI/2的积分 求∫sqrt(1+sin(x)^2)dx 区间为 0 到 pie/2 lim x->0(sqrt(sin(1/x^2)) 求极限 matlab参数方程绘图问题t=0:pi/1000:3*pi k=fix(2*t/pi)+1; y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k*sin(t); x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k*cos(t); plot(x,y) axis equal 为什么不能运行啊, matlab计算下面的公式.R=0.32;T=12.5;m=0.62;x=(0:pi/100:pi);x2=(0:pi/50:2*pi);l=(2:0.1:12);k1=(2.*pi./l).*(sqrt((sin(x).*cos(x2)-sqrt(3)./2).^2+(sin(x).*sin(x2)).^2));k2=(2.*pi./l).*(cos(x)+0.5);r=(R.*T.^2./(4.*pi.*m.^2)).*(1+0.5.*cos(x)-(sqrt(3 求arccos(sqrtx)/sqrt(1-x)在(0,1/2)上的定积分我是用cost替换sqrt(x)来做,做出的答案是-pi+((sqrt2)/4)pi+sqrt2, 如何用几何画板画出y=2sqrt(3)*sin((pi/6)*x)在[0,4]之间的图象 sin(x/2) = 2/3 [0≤x≤pi/2] cosx?tanx?sin(x/4) sin(x/2) = 2/3 [0≤x≤pi/2] 怎样求:(要程序!1) cosx?tanx?sin(x/4) Mathematica求数值解,错在哪?h = 4.13566743*(10^-15)m = 0.1*9.109*(10^-31)Do[NSolve[(0.4 - 2*y)/(2*Sqrt[0.4*y - y^2])*Sinh[Sqrt[8*Pi^2*m*(0.4 - y)/h^2]*x/2]*Sin[Sqrt[8*Pi^2*m*y/h^2]*x/2] + Cosh[Sqrt[8*Pi^2*m*(0.4 - y)/h^2]*x/2]*Cos[Sqrt[8*Pi^2 matlab三维图程序:[X,Y]=meshgrid([200:2:300],[-pi/4:pi/100:pi/4]);M=-pi/4:pi/100:pi/4;f=sqrt(1-((1600+(X.*cos(M+pi/4)-0.707*X+40*sin(Y)).^2+(X.*sin(M+pi/4)-0.707*X-40*cos(Y)).^2-(0.707*X-40*sin(Y)).^2-(0.707*X+40*cos(Y)).^2)./(80*X)).^2);Z=(pi/ 高数极限题,x->0的极限?f=x^2/(sqrt(1+x*sin(x))-sqrt(cos(x))); 4/3 求工程! matlab解方程画图2*tan(0.5*sqrt(8*x^2-y^2))/(sqrt(8*x^2-y^2))-tan(sqrt(x^2-y^2))/sqrt(x^2-y^2)=0,其中x=4*pi*sqrt(8.854*4*pi*10^(-19))/f,求画出f-y的曲线,其中0写错了,其中x=2*pi*sqrt(8.854*4*pi*10^(-19))*f MATLAB:Error using ==> inlineeval fplot('[ (1/((sqrt(2*pi))*1))*(exp(-(x.^2)/(2*1^2))),(1/((sqrt(2*pi))*2))*(exp(-(x.^2)/(2*2^2))),(1/((sqrt(2*pi))*4))*(exp(-(x.^2)/(2*4^2))),(1/((sqrt(2*pi))*(220/100)))*(exp(-(x.^2)/(2*(220/100)^2))) ]