作业帮6x^2-5xy-6y^2-2xz-23yz-20z^2=_______
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6x^2-5xy-6y^2-2xz-23yz-20z^2=_______
6x^2-5xy-6y^2-2xz-23yz-20z^2=_______
6x^2-5xy-6y^2-2xz-23yz-20z^2=_______
6x^2-5xy-6y^2-2xz-23yz-20z^2=_______
=(2x-3y)(3x+2y)-2xz-23yz-20z^2,(把前三项用十字相乘法因式分解）
所以设：原式=(2x-3y+az)(3x+2y+bz)
展开得：=(2x-3y)(3x+2y)+(2x-3y)bz+az(3x+2y)+abz^2
=(2x-3y)(3x+2y)+(2b+3a)xz-(3b-2a)yz+abz^2
左右对应相等,则有：
2b+3a=-2
3b-2a=23
ab=--20
解得：a=5,b=-4
所以原式=(2x-3y+5z)(3x+2y-4z)
6x^2-5xy-6y^2-2xz-23yz-20z^2 因式分解
因式分解:6x^2-5xy+6y^2-xz-23yz-20z^2
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