证明sin(4A)sin(2A)(1-cos(2A)) cos(4A)cos(2A)(1 cos(2A))=cos(2A)(1 cos(6A))应该是sin4Asin2A(1-cos2A) + cos4Acos2A(1+cos2A)=cos2A(1+cos6A)

三角形ABC中证明 COSA+COSB+COSC=1+4SIN(A/2)*SIN(B/2)*SIN(C/2) 三角形ABC中证明 COSA+COSB+COSC=1+4SIN(A/2)*SIN(B/2)*SIN(C/2) 证明cosA＋cosB＋cosC=1+4sin(A/2)sin(B/2)sin(C/2)证明：cosA＋cosB＋cosC=1+4sin(A/2)sin(B/2)sin(C/2)尽量详细一点选做cosA+cosB+cosC=1+4sin(A/2)sin(B/2)sin(C/2) cos(180-B-C)+cosB+cosC=1+2sin(A/2)[2sin(B/2)sin(C/2)] cos(180-B-C)+cosB+cosC 证明:sin^4a+cos^4a=1-1/2sin^22a 三角形ABC 证明sin(A/2)*sin(B/2)*sin(C/2) 证明 SIN²A+SIN²B-SIN²C=2SINASINBCOSC 【证明】Sin A+sin B=2Sin 22 懂得进.证明,sina+sin(a+b)+sin(a+2b)+...sin(a+nb)=sin(a+ab/2)sin[(n+1)b/2]/sin(b/2) 证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1 sina(cosa)^3=1/4sin 2a+1/8sin 4a证明过程 证明sin(a+b)sin(a-b)=sin^2 a-sin^2 b, 证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a 一道简单的三角比证明题求证：4sin[(b-c)/2]sin[(a-b)/2]sin[(c-a)/2]=sin(b-c)+sin(a-b)+sin(c-a)sin2x(cos2y-1)+sin2y(cos2x-1) =-2sin2x(siny)^2-2sin2y(sinx)^2有一个负号啊~但是另一边化简出来没有负号，难道cos2y=2(siny)^2+ 证明sin^2a+sin^2β+1>sina*cosa+sina+sinβ 用正弦定理证明a+b/c=sin A+sin B/sin c 证明恒等式tan a*sin a/tan a-sin a=1+cos a/sin a 证明 sin^4a+cos^4a=1-2sin^2a乘以cos^2a 证明sin^4a-cos^4a=sin^2a-cos^2a